Z^2-(7+5i)+(8+16i)=0

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Solution for Z^2-(7+5i)+(8+16i)=0 equation: 



^2-(7+5Z)+(8+16Z)=0

We add all the numbers together, and all the variables

-(5Z+7)+(16Z+8)+^2=0

We add all the numbers together, and all the variables

-(5Z+7)+(16Z+8)=0

We get rid of parentheses

-5Z+16Z-7+8=0

We add all the numbers together, and all the variables

11Z+1=0

We move all terms containing Z to the left, all other terms to the right

11Z=-1

Z=-1/11

Z=-1/11

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